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type error involving 'include' and applicative functors #6786

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vicuna opened this issue Feb 17, 2015 · 2 comments
Closed

type error involving 'include' and applicative functors #6786

vicuna opened this issue Feb 17, 2015 · 2 comments
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@vicuna
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vicuna commented Feb 17, 2015

Original bug ID: 6786
Reporter: ceastlund
Assigned to: @lpw25
Status: resolved (set by @gasche on 2016-08-30T08:30:02Z)
Resolution: fixed
Priority: normal
Severity: minor
Target version: 4.03.1+dev
Fixed in version: 4.04.0 +dev / +beta1 / +beta2
Category: typing
Has duplicate: #6788
Monitored by: @lpw25 @yallop

Bug description

A specific pattern of using 'include' does not type check. It seems like the type checker can do better just by updating some module paths more aggressively.

The behavior I see is that Make_ok1 and Make_ok2 compile fine, but the very similar functor Make_bad does not. The code is in the box below; here is the compile error:

========================================

  Error: Signature mismatch:
         Modules do not match:
           sig
             module C : sig module T : sig  end type t = Make(T).t end
             module T = C.T
             type t = Make(T).t
           end
         is not included in
           sig type t module C : sig type t = t end end
         In module C:
         Modules do not match:
           sig module T : sig  end type t = Make(T).t end
         is not included in
           sig type t = C.t end
         In module C:
         Type declarations do not match:
           type t = Make(T).t
         is not included in
           type t = t

Steps to reproduce

module type S = sig type t end
module Make (M : sig end) : S = struct type t end

module Make_ok1 (M : sig end) : sig

type t
module A : S with type t = t

end = struct

module A = struct
include Make (struct end)
end
include A

end

module Make_ok2 (M : sig end) : sig

type t
module B : S with type t = t

end = struct

module T = struct end
module B = struct
include Make (T)
end
include B

end

module Make_bad (M : sig end) : sig

type t
module C : S with type t = t

end = struct

module C = struct
module T = struct end
include Make (T)
end
include C

end

@vicuna
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vicuna commented Aug 30, 2016

Comment author: @gasche

The example code above type-checks in my 4.04 branch with the following inferred signature:

module type S = sig type t end
module Make : functor (M : sig end) -> S
module Make_ok1 :
functor (M : sig end) -> sig type t module A : sig type t = t end end
module Make_ok2 :
functor (M : sig end) -> sig type t module B : sig type t = t end end
module Make_bad :
functor (M : sig end) -> sig type t module C : sig type t = t end end

Can this issue be closed or does the problem still occur in more complex scenarios?

@vicuna
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vicuna commented Aug 30, 2016

Comment author: @lpw25

I think it can probably be closed. I'm pretty sure it is an instance of what

#708

fixes.

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