[
Home
]
[ Index:
by date
|
by threads
]
[ Message by date: previous | next ] [ Message in thread: previous | next ] [ Thread: previous | next ]
[ Message by date: previous | next ] [ Message in thread: previous | next ] [ Thread: previous | next ]
| Date: | -- (:) |
| From: | Claude Marche <Claude.Marche@l...> |
| Subject: | Re: nth_root of num? |
>>>>> "N Hur" == N Hur <mapnh@maths.bath.ac.uk> writes:
N Hur> Thank you.
N Hur> But running your code for example,
N Hur> root_floor 3 (Int 2) (* menaing third_root of 2 *);;
N Hur> gives 1, while what we want is 1.2599210498 ...
Sorry, I misunderstood your question. I though you where interested in
computing the nth root of a big_num. If you are interested in
computing the nth root of a float, I really don't understand why you
are using big nums.
An algorithm for computing the nth root of a float is easy :
let nth_root n x = exp (log(x)/.(float_of_int n));;
Hope this helps. If it doesn't answer to your question, please explain
your problem more precisely.
- Claude
--
| Claude Marché | mailto:Claude.Marche@lri.fr |
| LRI - Bât. 490 | http://www.lri.fr/~marche/ |
| Université de Paris-Sud | phoneto: +33 1 69 15 64 85 |
| F-91405 ORSAY Cedex | faxto: +33 1 69 15 65 86 |