The Pentium NonBug
 David McClain
[
Home
]
[ Index:
by date

by threads
]
[ Message by date: previous  next ] [ Message in thread: previous  next ] [ Thread: previous  next ]
[ Message by date: previous  next ] [ Message in thread: previous  next ] [ Thread: previous  next ]
Date:   (:) 
From:  David McClain <dmcclain@a...> 
Subject:  The Pentium NonBug 
In light of my recent trip around the mulberry bush, I thought I would post a preamble from some of my code for everyone's sake.  DM (*  *) (* Considerable care has been taken to be IEEE correct *) (* in the face of distinct (+0.0) and (0.0). *) (* The rules of the game are: *) (* Addition => commutative a + b = b + a *) (* Subtraction => anticommutative a  b = (b  a) *) (* Multiplication => commutative a * b = b * a *) (* Division => inversecommutative a / b = 1.0 / (b / a) *) (* Identity under addition: *) (* x + (0.0) = x but x + (+0.0) != x *) (* Identity under subtraction: *) (* x  (+0.0) = x but x  (0.0) != x *) (* Negation by subtraction: *) (* (0.0)  x = neg x (= FCHS x) but (+0.0)  x != neg x *) (* Equivalence of subtraction by addition of negative: *) (* a  b = a + neg b *) (* Distribution of negation: *) (* a  b = (b  a) = b  (a) = b + a *) (* ;; remember that addition is commutative *) (* Complex conjugation by negation: *) (* conj(re,im) = (re, im) != (re, 0  im) *) (* Since the constant 0.0 generally denotes (+0.0) and since it is *) (* generally difficult to determine the sign of a given *) (* zero constant value, one simply cannot assume that: *) (* 0.0 + x = x *) (* x  0.0 = x *) (* 0.0  x = neg x *) (* Rather, one must carry out what appears to be a null operation, *) (* and be certain to negate when appropriate, instead of subtracting *) (* from zero. *)