>  In the stdlib directory of ocaml 2.04 , I find the result of make to be
> something like what is shown below. What is the significance of
> 'ocamlrun' here? 
> 
> ../boot/ocamlrun ../boot/ocamlc -g -nopervasives -c pervasives.mli
> ../boot/ocamlrun ../boot/ocamlc -g -nopervasives -c pervasives.ml
> ../boot/ocamlrun ../boot/ocamlc -g -c list.mli 
> 
> The problem I face is that I have a ocamlrun cross system which cannot run
> on Linux. I am asking this because one can always compile using
> 'ocamlc' directly ie. without using ocamlrun.

Yes, but only once the system has been installed.  (ocamlc is a script
starting with e.g. #!/usr/local/bin/ocamlrun, so it can be run
directly only after ocamlrun is installed in /usr/local/bin.)  While
the system is being built, it is necessary to say where ocamlrun
resides.

For your particular situation (cross-compiling), as I explained to you
before, you want boot/ocamlrun to be the native (not cross-compiled)
runtime system, and byterun/ocamlrun to be the cross-compiled,
runtime system, suitably modified for your target architecture.

- Xavier Leroy