Damien Doligez wrote:
> 
> >From: Max Skaller <maxs@in.ot.com.au>
> 
> >        let rec x'() = 1 :: x()'
> >        let x = x'()
> >
> >Seems to work fine. Of course, this will loop forever in an eager
> >language: the result is an infinite list of 1s.
> 
> Looping forever is not quite the same as returning an infinite list
> of 1s, which is what the current implementation does for
>     let rec x = 1::x

I don't understand: to construct an infinite list of 1's would seem to
me to take infinite time in an eager language. So it comes to the same
thing, doesn't it?

-- 
John (Max) Skaller, mailto:skaller@maxtal.com.au
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