Hi,

On Sat, Dec 30, 2000 at 11:30:57AM -0800, Chris Hecker wrote:

> type foo = {bar:float; baz:int };;
> let a = {bar = 1.;baz = 1};;
> print_members_camlp4 a;;
> 
> Where print_members_camlp4 is hooked by camlp4 to iterate over the
> members of whatever record was passed to it (or error at compile
> time if it's not a record)?  That's not possible?

Camlp4 does not know what a type definition is: for it, it is just a
syntax thing. Therefore, in the line "print_member_camlp4 a", Camlp4
does not know what "a" is: for it, it is just "the identifier a",
that's all. The fact that it is a variable previously defined of type
"foo" is typing. If you want to treat that at Camlp4 time, you have to
write a types inference algorithm. A compiler...

-- 
Daniel de RAUGLAUDRE
daniel.de_rauglaudre@inria.fr
http://cristal.inria.fr/~ddr/