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Why can't I use val mover : < move : int -> unit; .. > list -> unit ?
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Mattias Waldau
-
Brian Rogoff
-
Mattias Waldau
- Michel Schinz
- Sylvain BOULM'E
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Mattias Waldau
- Alain Frisch
- Sylvain BOULM'E
-
Brian Rogoff
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| Date: | -- (:) |
| From: | Sylvain BOULM'E <Sylvain.Boulme@l...> |
| Subject: | Re: Why can't I use val mover : < move : int -> unit; .. > list -> unit ? |
> I understand the principle that the compiler must be sure that everywhere I
> use the list, the elements will be of the right type. In this case each
> element must have the method move.
>
> However, it seems to me that in this case the compiler has already done the
> complex part, i.e. realizing that if all objects have a move-method, then
> everything is ok. So I don't see the point that I have to coerce explicitily
> when putting elements into the list.
>
Such a coercion is not always possible: forget the "unnecessary" methods has not always a meaning. For instance, let's have an example a bit more complex than yours :
In the context :
class pt =
object (_:'a)
method compare (x:'a) = true
end
class qt (i:int) =
object (s:'a)
val mutable state = i
method compare (x:'a) = x#get = s#get
method get = state
end
let p = new pt and q1 = new qt 1 and q2 = new qt 2;;
(** test if x is comparable to all elements of l **)
(* val compare_iter : < compare : 'a -> bool; .. > list -> 'a -> bool *)
let compare_iter l x = List.fold_left (fun b y -> b && y#compare x) true l;;
compare_iter [p;p] p;;
compare_iter [q1;q2] q1;;
Both these expressions below are not well-typed :
compare_iter [q1;q2] p;;
compare_iter [(q1:> pt);(q2:> pt)] p;;
Indeed, an object of type "qt" can not be coerced to an object of type "pt" because an object of type "qt" needs an object with a "get" method as argument for "compare". What is interesting here with ocaml polymorphism, is that you can however have a function as "compare_iter" which can both handle "lists of pt" and "lists of qt".
Hope this helps,
Sylvain.