On Mon, Sep 03, 2001 at 10:53:56PM -0400, Jon Moore wrote:
> In the code you wrote above, "fso" gets bound to () (and not to a function)
> after flushing stdout once. So the name and color functions you wrote are
> doing prints, and returning units, rather than invoking the flush as you
> thought. Thus, this is why the output becomes bursty (you're not actually
> flushing).

Heh, a pretty obvious mistake now that I look at it...  If it's fully
applied it's only the return value, otherwise it's a partially applied
function/closure awaiting more args.  All that lambda calculus stuff. :)

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