On Tue, 18 Sep 2001, Patrick M Doane wrote:


> (* The first works as I would expect, the second gives a very unexpected
> type. There seems to be some kind of unexpected unification going on
> between terms. *)
> 
> let h1 (#b as x1) (#c as x2) = `A [x1; x2]

here #b is a pattern, it is the same as
let h1 (`B as x1) (`C as x2) = `A [x1; x2]



> let h2 (x1 : #b) (x2 : #c) = `A [x1; x2]

but here it is a type expression, and is the same as
let h2 (x1 : [< `B]) (x2 : [< `C]) = `A [x1; x2]

and in a list, all argument must have the same type, tou take the
intersection of both and obtain [ ]



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