You have to use the "parameterization trick" since syntax doesn't work.

> Example :
> 
>   class type c_foo =
>   object
>     val val_foo : t_foo
>   end
> and
>   t_foo = Foo of c_foo

type 'a _t_foo = Foo of 'a

class type c_foo =
  object
    val val_foo : c_foo _t_foo
  end

type t_foo = c_foo _t_foo

That'll get you a type t_foo that does what you want.

Jeremy
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