stalkern2 <stalkern2@tin.it> writes:

> Beginner's opinion:
> I think that the compiler/interpreter is clear: 
> 	'a->'b->'a 
> 	is not 
> 	'a->'a->'b->'a
> and that you just let the function starve before giving it the last
> meatball. 

It's not the reason : in ocaml, you can do partial application (giving
not all argument to a function). 

it steel strange because 

let mAny: 'a -> int -> 'a = fun succ0 input -> succ0;;
let ans0 = true;;
let x = mAny (mAny ans0);;
x 1 2;;

type checks...

-- 
Rémi Vanicat
vanicat@labri.u-bordeaux.fr
http://dept-info.labri.u-bordeaux.fr/~vanicat
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