On Mon, Dec 02, 2002 at 04:55:06PM +0100, altavillasalvatore@libero.it wrote:
> Hi all,
> I would want to know if a function exists that allows me to make this:
> 
> ["123";"45";"678"]  ->  [1;2;3;4;5;6;7;8;].

let f l = 
  let ret = ref [] in
  String.iter 
    (fun c -> ret := ((int_of_char c) - (int_of_char '0')) :: !ret) 
    (List.fold_left (^) "" l);
  List.rev !ret;;
  
f ["123";"45";"678"];;

Cheers,
Issac Trotts

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