Pietro Abate writes:
 > Hi all,
 > I get this error trying to compile the file below:
 > 
 > File "pp.ml", line 28, characters 22-24:
 > Signature mismatch:
 > Modules do not match:
 >   sig type t = BB.t val toast : t -> t -> bool end
 > is not included in
 >   sig type t = AA.t val toast : t -> t -> bool end
 > Type declarations do not match:
 >   type t = BB.t
 > is not included in
 >   type t = AA.t
 > 
 > how can I force BB.t to be the same as AA.t ?
 > why it's not enforced by the functor declaration (with type...) ?

Types AA.t and BB.t are abstract, due to the declarations "module AA :
A1" and "module BB : A2" and  to the fact that "t" is abstract in both
interfaces A1 and A2. You should write instead

	module AA : A1 with type t = int = ...
	module BB : A2 with type t = int = ...
	module C = Make (AA) (BB)

(Another possibility is  to declare "type t =  int" in both signatures
A1 and A2 but it is probably not what you want to do.)

-- 
Jean-Christophe Filliâtre (http://www.lri.fr/~filliatr)


 > -----------------
 > module type A1 = sig
 >     type t 
 >     val test : t -> t -> bool
 > end
 > 
 > module type A2 = sig
 >     type t 
 >     val toast : t -> t -> bool
 > end
 > 
 > module Make (A : A1 ) (B : A2 with type t = A.t) = struct
 >     let fifi a b c =
 >         if c > 1 then A.test a b 
 >         else B.toast b a
 > end
 > 
 > module AA : A1 = struct 
 >     type t = int
 >     let test f1 f2 = true
 > end
 > 
 > module BB : A2 = struct
 >     type t = int
 >     let toast f1 f2 = false
 > end
 > 
 > module C = Make (AA) (BB)
 > 
 > ---------------------
 > 
 > -- 
 > Civilization advances by extending the number
 > of important operations which we can perform 
 > without thinking. (Alfred North Whitehead)
 > 
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