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[Caml-list] Int overflow in literals
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| Date: | -- (:) |
| From: | Issac Trotts <ijtrotts@u...> |
| Subject: | Re: [Caml-list] Int overflow in literals |
On Thu, Oct 30, 2003 at 10:36:24PM +0100, Frederic van der Plancke wrote:
>
>
> Issac Trotts wrote:
> >
> > On Thu, Oct 30, 2003 at 02:53:32PM +0100, Marcin 'Qrczak' Kowalczyk wrote:
> > > I understand that int overflow is not checked on arithmetic for
> > > efficiency reasons, but IMHO it would be better if it was checked
> > > at least in literals. When someone writes 10000000000, he certainly
> > > does not mean -737418240.
> >
> > If you want to be sure that the number is correctly stored, you can use
> > Int64:
> >
> > Int64.of_string "10000000000"
> >
> > Issac
>
> That was not my problem. My problem was to be able to read a list of integers from a file and be warned in case of overflow. And to be able to rely on int_of_string for that purpose. I got hit... of course now I know, but other innocent programmers may get hit in the future as well. (Not to speak of the not-so-innocent people who wrote this nice OCaml compiler ;-)
Here's a way to do what you want, at least for numbers
betweeen -9223372036854775808 and 9223372036854775807 :
let safe_int_of_string str =
let i = int_of_string str in
let i64 = Int64.of_string str in
if i64 = Int64.of_int i then i else failwith "overflow"
# safe_int_of_string "10000000000";;
Exception: Failure "overflow".
# safe_int_of_string (string_of_int 1073741823)
;;
- : int = 1073741823
-ijt
>
> Fr?d?ric.
>
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