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| Date: | -- (:) |
| From: | Diego Olivier Fernandez Pons <Diego.FERNANDEZ_PONS@e...> |
| Subject: | [Caml-list] try ... with and stack overflow |
Bonjour,
I cannot figure what is puzzling the Caml compiler in some code I
wrote. It seems to be related to the try ... with construction against
tail-recursive optimization. Or am I doing a semantical mistake (that
is to say that I am believing the two codes to be equivalent when they
are not) ?
Some explanations : I first wrote an optimized search procedure (for a
branch and bound) and then wanted to compare it against the naive
version.
It works in the following way :
- goes down the tree by the left branch until reaches a leaf
- if the leaf is a solution, all the inexplorated branches are put in
closures and added to the 'continuation queue'
- if the leaf fails, an exception is raised and the deepest
unexplorated right branch is taken instead (try ... left_branch ...
with Failed -> ... right_branch ...)
exception Failed
type location = Left | Right
(* Optimized depth-first search *)
type 'a goal = Goal of ('a goal list -> 'a * 'a goal list)
let rec solve = function
| [] -> []
| Goal g :: tail ->
try
let (result, continuations) = g tail in
result :: solve continuations
with Failed -> solve tail
let rec dfs continuations = fun f data level ->
match level with
| 0 -> (f data, continuations)
| n ->
try
let
right = Goal (fun c -> dfs c f (Right :: data) (n - 1))
in
dfs (right :: continuations) f (Left :: data) (n - 1)
with Failed -> dfs continuations f (Right :: data) (n - 1)
let make_dfs = fun f n -> Goal (function c -> dfs c f [] n)
The naive version works in the same way but closures are
systematically constructed for both left and right branches.
(* Simple depth-first search *)
type 'a simpleGoal =
| Result of 'a
| Closure of ('a simpleGoal list -> 'a simpleGoal list)
let rec simple_solve = function
| [] -> []
| Result x :: tail -> x :: simple_solve tail
| Closure f :: tail ->
try
simple_solve (f tail)
with Failed -> simple_solve tail
let rec simple_dfs continuations = fun f data level ->
match level with
| 0 -> Result (f data) :: continuations
| n ->
let
left = Closure (fun c -> simple_dfs c f (Left :: data) (n - 1)) and
right = Closure (fun c -> simple_dfs c f (Right :: data) (n - 1))
in
left :: right :: continuations
let make_simple_dfs = fun f n ->
Closure (function c -> simple_dfs c f [] n)
Both seem to be working well
let rec print_location = function
| [] -> ()
| Left :: tail -> print_location tail ; print_string "Left "
| Right :: tail -> print_location tail ; print_string "Right "
let all_fail_trace = function location ->
print_location location ;
print_newline();
raise Failed
# solve [make_dfs all_fail_trace 2];;
Left Left
Left Right
Right Left
Right Right
- : '_a list = []
# simple_solve [make_simple_dfs all_fail_trace 2];;
Left Left
Left Right
Right Left
Right Right
- : '_a list = []
But the naive version seems to have a tail-recursion problem
# solve [make_dfs (fun loc -> raise Failed) 15];;
- : '_a list = []
# simple_solve [make_simple_dfs (fun loc -> raise Failed) 15];;
Stack overflow during evaluation (looping recursion?).
Then I changed the following code
let rec simple_solve = function
| [] -> []
| Result x :: tail -> x :: simple_solve tail
| Closure f :: tail ->
try
simple_solve (f tail)
with Failed -> simple_solve tail
by
| Closure f :: tail ->
simple_solve (try
f tail
with Failed -> tail)
and this time it worked
# solve [make_dfs (fun loc -> raise Failed) 15];;
- : '_a list = []
# simple_solve [make_simple_dfs (fun loc -> raise Failed) 15];;
- : '_a list = []
Diego Olivier
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