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| Date: | -- (:) |
| From: | Brian Hurt <bhurt@s...> |
| Subject: | Re: [Caml-list] Closure & Ref |
On Mon, 17 Nov 2003, chris.danx wrote:
> Hi,
>
> I was toying with ocaml just now and have successfully written a
> function that takes and int that produces a function that takes an int
> to add to the original.
>
> let prodAdd x =
> let value = ref x in
> fun y -> !value + y;;
Since you're not setting the reference, why have one? Instead, try:
let prodAdd x = fun y -> x + y
But we can do it simpler than that:
let prodAdd x y = x + y
And use partial function application. (prodAdd 4) returns a function
which adds 4 to whatever int parameter passed to it.
>
> Now I want to do a function that takes a ref to a list and returns a
> function that adds items to the list and produce a function that returns
> another that returns the list. How do I do that?
>
> let prod_list_acc a =
> fun x -> a := x :: !a; true;;
>
> let return_acc a =
> fun () -> !a;;
>
> but that gives a "unit -> int list" =. How do you get a copy of the
> list values?
Now you're setting the reference. But prod_list_acc and return_acc need
to share the reference.
Now, I for one, hate globals. This is the result of programming for years
in C. What I would do is write a function which returns a tuple of two
functions, and accumlator function and a current list function, like:
let make_listacc () =
let r: int list ref = ref [] in
let acc x = r := x :: !r
and lst () = !r
in acc, lst
;;
This allows you to have multiple different lists being constructed
independently. Note, the above code is actually more generic than it
looks- I had to add an explicit type statement to make it "come out
correct". Without the explicit type information:
let make_listacc () =
let r = ref [] in
let acc x = r := x :: !r
and lst () = !r
in acc, lst
;;
The function is both clearer than the original, and creates lists of any
type, not just ints. If you hear me bitching about C++ and Java making
generics "special and extraordinary", this is a classic example of what
I'm kvetching about.
You'd use make_listacc like:
let my_acc, my_list = make_listacc() in
my_acc 3;
my_acc 4;
my_acc 5;
my_list ()
;;
The above code returns [5;4;3] (note, the list is built backward!).
The most common way to access members of a list is to use what is called
"list comprehensions". Don't let the names fool you- these are just
functions that walk the list and do something on every element of the
list. Look at List.iter and List.fold_left. So let's say I want to take
a list of ints and sum them. I could simply do:
List.fold_left (fun x y -> x + y) 0 lst
Note that + is just a function, so I could just as easily have done:
List.fold_left (+) 0 lst
to do the same thing.
The second most common way to access members of a list is to write a short
recursive function. Say I wanted to know if the list contained a given
number. I might write:
let rec has_num x = function
| [] -> false
| h :: t -> if (h == x) then true else has_num x t
;;
If you want to access specific members of a list (other than the head), I
wouldn't recommend using a list, but instead some other datastructure (an
array or hash table being the obvious choices).
--
"Usenet is like a herd of performing elephants with diarrhea -- massive,
difficult to redirect, awe-inspiring, entertaining, and a source of
mind-boggling amounts of excrement when you least expect it."
- Gene Spafford
Brian
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