On Fri, Feb 27, 2004 at 10:32:29PM +0100, Basile STARYNKEVITCH wrote:
> On Fri, Feb 27, 2004 at 02:29:50PM -0600, Kevin S. Millikin wrote:
> > I'm trying to figure out what I can rely on about physical equality. 
> >  I've checked the OCaml manual but can't seem to find what I want to 
> > know.
> > 
> > Presume
> > 
> > # type t = V0 | V1 of int;;
> > type t = V0 | V1 of int
> > 
> > # V0 == V0;;
> > - : bool = true
> > 
> > V0's are the same.  Is this guaranteed?
> 
> Yes.

Is it?

"On non-mutable structures, the behavior of (==) is
implementation-dependent;" [1]

[1] http://caml.inria.fr/ocaml/htmlman/libref/Pervasives.html

-- 
: Michal Moskal :: http://www.kernel.pl/~malekith :: GCS !tv h e>+++ b++
: When in doubt, use brute force. -- Ken Thompson :: UL++++$ C++ E--- a?

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