Rahul Siddharthan wrote:
> I have a question: suppose I have a list l1, and I want to create a new
> list l2 with only one copy of any repeated members of the first list
> (eg, l1=[1;2;3;4;3;4;5;6;5] -> l2=[1;2;3;4;5;6])

let unique l = List.rev (List.fold_left (fun results x -> if 
List.mem x 		results then results else x::results) [] l);;

unique [1;2;3;4;3;4;5;6;5];;
- : int list = [1; 2; 3; 4; 5; 6]

List.rev is not tail recursive, so you wouldn't want to use this 
function on industrial size lists.

You might want to check out the ocaml_beginners@yahoogroups.com mailing 
list.  That is a good place to ask questions like this.

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