Rahul Siddharthan wrote:
> I have a question: suppose I have a list l1, and I want to create a new
> list l2 with only one copy of any repeated members of the first list
> (eg, l1=[1;2;3;4;3;4;5;6;5] -> l2=[1;2;3;4;5;6])

Here's one way:

let unique ls =
   let uniq_aux new_ls old_elem =
     match new_ls with
       | [] -> [ old_elem ]
       | hd :: tl when hd = old_elem -> new_ls
       | _ -> old_elem :: new_ls
   in
   let sorted = List.sort compare ls in
     List.rev (List.fold_left uniq_aux [] sorted) ;;

Ben

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