On Mon, 2004-08-30 at 18:25, Ville-Pertti Keinonen wrote:
> skaller wrote:

> >	e1 ; e2
> >
> >evaluates e1, then e2 (for side effects).
> >  
> >
> e1 is evaluated for side-effects, the value of e2 is the value of the 
> entire expression, it does not need to be of type unit.
> 
> You could think of ; as having the type unit -> 'a -> 'a

Yup, that's more correct -- sry for prior inaccuracy.

-- 
John Skaller, mailto:skaller@users.sf.net
voice: 061-2-9660-0850, 
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