I am experiencing unexpected functor behaviour using the 3.08.1 compiler 
(both ocamlc and ocamlopt). The 3.07+2 compiler works great and does not 
have this problem. I am wondering if it is a known bug, despite the fact 
that i was not able to replicate this behaviour with a small example(it 
only happens in a large project im working on, and only in 3.08.1).

In a functor:

module A(B:Bsig) = struct
module B =B
open B

let x=B.name
let y = name

end

when i make two instances of functor A using two different input modules 
B1 and B2

A1=A(B1)
A2=A(B2)

i sometimes find that A2.y refers to B1.name as opposed to B2.name , 
while A2.x correctly refers to B2.name . Hence, it seems that using the 
open statement when creating A2 is "opening" B1 as opposed to B2 .....
for some reason i wasnt able to replicate this behaviour in a small 
example, so i dont know under exactly what circumstances this happens....
has anybody else seen this kind of behaviour before? does it have 
anything to do with how open is defined inside functors?



-------------------
To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr
Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/
Beginner's list: http://groups.yahoo.com/group/ocaml_beginners