suppose I have

  val x : int ref Lazy.t

and I want to 'incr' it, but want to keep it lazy.  i.e., if i start with:

  let x = Lazy.lazy_from_fun (fun () -> ref 0)

then i run my lazy_incr on it, I want:

  let y = Lazy.force x

to return 1

but i only want 'incr' to be run when I Lazy.force x.  is there a way to 
accomplish this?

  

-- 
 Hal Daume III                                   | hdaume@isi.edu
 "Arrest this man, he talks in maths."           | www.isi.edu/~hdaume