> The following compiles fine:
>
>   type t = { keyword : string; cost : float option; }
>
>   let f =
>     function
>       | { keyword = keyword } when keyword.[0] = '-' -> keyword
>       | { keyword = keyword; cost = None } -> keyword
>       | _ -> failwith "whatever"
>
> But this, which surely is equivalent, fails with a syntax error at the
> second '|' character:
>
>   type t = { keyword : string; cost : float option; }
>
>   let f =
>     function
>       | { keyword = keyword } when keyword.[0] = '-' (* -> keyword *)
>       | { keyword = keyword; cost = None } -> keyword
>       | _ -> failwith "whatever"
>
> OCaml 3.08.1.
>
> Is this a parsing bug?
>
> Rich.

I guess you can't have a "when" clause between two patterns, that sounds
logical since it applies to all patterns in the same "group".

Nicolas Cannasse