Hello,
2005/6/26, Sen Horak <sen.horak@gmail.com>:
> let parse = parser
>       [<'Kwd "name=";'String t>] -> wm#setname t
>   |  ...
> 
> let istream = of_channel stdin
> The program exits with a Stream.Failure exception. The "stream
> builders" documentation clearly says that we are not to mix the of_*
> functions to build streams with <> streams - so I guess this is
> expected. Although I've come across some examples that use of_string
> to build the char stream and use the lexer on it.
> 

I can be wrong, but I think that the documentation prohibits stuff like
let s = Stream.of_string "foo" in [< s; s >], that is building a
stream with both the of_* functions and the [< >] notation. This is
not the case here, since [< >] is used only for pattern matching.

Concerning your original problem, I think that the main issue is that
"name=" is not a valid keyword for lexer. Try to split it in "name"
and "=" (cf documentation of Genlex.token), i.e. do something like
let lexer = Genlex.make_lexer ["name"; "="; ...]
let parse = parser [< 'Kwd "name"; 'Kwd "="; 'String t >] -> ... 

-- 
E tutto per oggi, a la prossima volta
Virgile