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Rephrasing of dynamic module selection problem
-
Nathan Cooprider
- Martin Jambon
- brogoff
- Virgile Prevosto
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Date: | 2006-02-21 (12:14) |
From: | Virgile Prevosto <virgile.prevosto@m...> |
Subject: | Re: [Caml-list] Rephrasing of dynamic module selection problem |
Hello, Le lun 20 fév 2006 17:54:32 CET, Nathan Cooprider a écrit: > [coop@ender example]$ cat main.ml > module Hello1 = struct > #include "hello1.ml" > end ;; > module Hello2 = struct > #include "hello2.ml" > end ;; This is not needed: the file hello1.ml implicitely defines a module Hello1 (same for hello2.ml and Hello2). > (* This works . . . *) > module H = Hello1 > (* But I would like this to be something like this instead: > let parameter = 1 > module H = > match parameter with > 1 -> Hello1 > | _ -> Hello2 > *) This might not completely solve your problem, but the following camlp4 extension allows you to use the following expression: choose_module H = match parameter with 1 -> Hello1 | _ -> Hello2 in let argument = 42 in let main () = H.print (H.of_int argument) in main ();; Note that the scope of H is the expression following the first "in" and not all the remaining of main.ml. This might be an issue, but it could be solved by the use of functors (e.g.: module type Hello = sig ... end module F (H: Hello) = struct ... end ... choose_module H = ... in let module FH = F(H) in ... ;; ) -------- choose_module.ml4 ---------- (* compile it with ocamlc -c -I +camlp4 -pp "camlp4o pa_extend.cmo q_MLast.cmo -impl" -impl choose_modules.ml4 to use it, ocamlc -c -pp "camlp4o choose_modules.cmo" main.ml Note that by default, camlp4 doesn't search for extension in the current directory, so that you may have to add a "-I ." directive *) open Pcaml;; let make_one_choice a mod_expr exp = let _loc = Lexing.dummy_pos, Lexing.dummy_pos in <:expr<let module $uid:a$ = $mod_expr$ in $exp$>> let choices = Grammar.Entry.create Pcaml.gram "choices" EXTEND expr: [[ "choose_module"; a = UIDENT; "="; "match" ; cond = expr; "with"; OPT "|"; l = LIST1 choices SEP "|"; "in"; e = expr -> let new_l = List.map (fun (patt,optwhen,expr) -> (patt,optwhen, make_one_choice a expr e)) l in <:expr< match $cond$ with [$list:new_l$] >> ]]; choices: [[ p=patt; w = OPT ["when"; e = expr -> e]; "->"; m = module_expr -> (p,w,m) ]]; END ------------------------------------- -- E tutto per oggi, a la prossima volta Virgile