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| Date: | -- (:) |
| From: | Christoph Bauer <christoph.bauer@l...> |
| Subject: | Re: [Caml-list] generic Hashtbl.to_array |
Hi,
> let to_array t =
> let init = ref None in
> begin try Hashtbl.iter (fun k v -> init := Some (k,v);
> raise Exit) t
> with Exit -> ()
> end;
> match !init with
> | None -> [| |]
> | Some i ->
> let a = Array.make (Hashtbl.length t) i in
> ignore (Hashtbl.fold (fun k v i -> a.(i) <- (k, v); i + 1) t 0);
> a
> ;;
it's curious, but this solution is slower than the others!
[skaller's solution seems to be the same, so I
include only this one in the "benchmark"]
Rate to_array_4 to_array_3 to_array_1b to_array_2
to_array_1
to_array_4 407+-0/s -- -16% -16% -17%
-17%
to_array_3 486+-2/s 19% -- [-0%] [-1%]
-1%
to_array_1b 487+-0/s 20% [0%] -- [-0%]
-1%
to_array_2 489+-2/s 20% [1%] [0%] --
-1%
to_array_1 491+-0/s 21% 1% 1% 1%
--
from http://ocaml-benchmark.sourceforge.net/doc/Benchmark.html
Benchmark.tablulate results prints a comparison table for a list of results
obtained by Benchmark.latencyN or Benchmark.throughputN with each function
compared to all the others. The table is of the type
Rate name1 name2 ... OR s/iter name1 name2 ...
name1 #/s -- r12 name1 # -- r12
name2 #/s r21 -- name2 # r21 --
... ...
where name1, name2,... are the labels of the tests sorted from slowest to
fastest and rij says how much namei is faster (or slower if < 0) than namej
(technically it is equal to (ri - rj) expressed in percents of rj where ri
and rj are the rates of namei and namej respectively).
If several results are associated to a given name, they are used to compute
a Student's statistic to check whether the rates are significantly
different. If ri and rj are not believed to be different, rij will be
printed between brackets.
(* compile with
ocamlopt -o to_array -I benchmark-0.7 unix.cmxa benchmark-0.7/benchmark.cmx
to_array.ml
*)
open Benchmark
let to_array_1 t =
let dummy = Array.init 0 (fun _ -> raise Not_found) in
fst
(Hashtbl.fold
(fun k v (a, i) ->
if i = 0 then
let a = Array.make (Hashtbl.length t) (k, v) in
(a, 0)
else (a.(i) <- (k, v); (a, i + 1)))
t (dummy, 0))
let to_array_2 t =
let init _ = fun () -> raise Not_found in
let a = Array.init (Hashtbl.length t) init in
ignore
(Hashtbl.fold (fun k v i -> a.(i) <- (fun () -> (k, v)); i+1) t 0);
Array.map (fun f -> f ()) a
let to_array_3 t =
Array.of_list (Hashtbl.fold (fun a b c -> (a, b) :: c) t [])
let to_array_1b t =
let a = ref (Array.init 0 (fun _ -> raise Not_found)) in
ignore
(Hashtbl.fold
(fun k v i ->
if i = 0 then
(a := Array.make (Hashtbl.length t) (k, v);
i)
else
((!a).(i) <- (k, v); i + 1))
t 0);
!a
let to_array_4 t =
let init = ref None in
begin try Hashtbl.iter (fun k v -> init := Some (k,v); raise Exit) t
with Exit -> ()
end;
match !init with
| None -> [| |]
| Some i ->
let a = Array.make (Hashtbl.length t) i in
ignore (Hashtbl.fold (fun k v i -> a.(i) <- (k, v); i + 1) t 0);
a
let h () =
let h = Hashtbl.create 100000 in
for i = 0 to (Hashtbl.length h) do
Hashtbl.add h (Random.int max_int) (Random.int max_int);
done;
h
let main () =
let h = h () in
let res = throughputN ~repeat:5 1
[("to_array_1", to_array_1, h);
("to_array_1b", to_array_1b, h);
("to_array_2", to_array_2, h);
("to_array_3", to_array_3, h);
("to_array_4", to_array_4, h); ] in
tabulate res
let () = main ()