float rounding
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Date:   (:) 
From:  Sean McLaughlin <seanmcl@c...> 
Subject:  float rounding 
Hello, I'm using Ocaml for an interval arithmetic application. I"m curious about what the Ocaml parser/compiler does to float constants. May I assume that for any constant I enter, eg. 3.1415... (for N digits of pi), that the compiler will give me a closest machine representable number? i.e., if I bound a constant by the previous and next floating point value to that given me by the compiler, will it always be the case that my original (mathematical) constant lies in that interval? Thanks, Sean