float rounding
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Date:   (:) 
From:  Florent Monnier <fmonnier@l...> 
Subject:  Re: [Camllist] float rounding 
> I'm using Ocaml for an interval arithmetic application. I"m > curious about > what the Ocaml parser/compiler does to float constants. May I assume > that for any constant I enter, eg. 3.1415... (for N digits of pi), that > the compiler will give me a closest machine representable number? > i.e., if I bound a constant by the previous and next floating point > value to > that given me by the compiler, > will it always be the case that my original (mathematical) constant > lies in that interval? For the concrete exemple of PI, perhaps you could use a mathematical calculation to get its best value: # 4. *. atan 1. ;;  : float = 3.14159265358979312 (but the last number '2' is wrong) For other constants, maybe there are equivalent things?