On Wed, 2007-05-02 at 20:35 +0200, Francois Pottier wrote:
> On Thu, May 03, 2007 at 02:29:17AM +1000, skaller wrote:

> > Yes, but you cannot write functions that take a state argument
> > because lexbuf is a fixed data type and there's no where to
> > add in any user state data.
> 
> But my point is that you never need to pass a state argument to a parser
> function. Instead, you can just have the function capture the address of the
> (mutable) state in its closure.

And mine is that you can't do that because the function is
generated with a fixed signature, whose only state data
is the lexbuf.

Joel pointed out this isn't so, if you use a functor and
construct it locally, then a 'global' variable of the
functor is actually localised: I admit I didn't think of
local dynamic instantiation.

-- 
John Skaller <skaller at users dot sf dot net>
Felix, successor to C++: http://felix.sf.net