English version
Accueil     À propos     Téléchargement     Ressources     Contactez-nous    

Ce site est rarement mis à jour. Pour les informations les plus récentes, rendez-vous sur le nouveau site OCaml à l'adresse ocaml.org.

Browse thread
Order of evaluation when constructing record values
[ Home ] [ Index: by date | by threads ]
[ Search: ]

[ Message by date: previous | next ] [ Message in thread: previous | next ] [ Thread: previous | next ]
Date: 2007-08-13 (07:12)
From: Jacques Garrigue <garrigue@m...>
Subject: Re: [Caml-list] Order of evaluation when constructing record values
From: "Jeff Meister" <nanaki@gmail.com>

> I ask for forgiveness in advance for this silly pedantic question.
> I think my question is best illustrated with an example. Say I have
> this simple record type for holding a date:
> type date = { year : int; month : int; day : int; }
> Now, I want to read the year/month/day values from stdin, and I know
> they will appear in that order. So I do the following:
> let today = {
>   year = read_int ();
>   month = read_int ();
>   day = read_int ();
> }
> For this to work, I need the ints to be read in the order given, or I
> could end up with a day of 2007 and a year of 11. Is there any
> guarantee that OCaml will follow that order of evaluation when
> constructing the record? Or do I have to force it with let-bindings
> like this:
> let today =
>   let y = read_int () in
>   let m = read_int () in
>   let d = read_int () in
>   { year = y; month = m; day = d; }
> Of course, it's not that big a deal for me to just use the let-binding
> method, but I'm curious, and it might make my code look nicer if I can
> rely on order of evaluation.

You definitely have to use let-bindings.
The order of evaluation without let-bindings is left unspecified in
the reference manual.
IIRC, in practice this should be right-to-left, following the
definition of the datatype (not the order in the function!), but this
does not seem a good idea to rely on that.

Jacques Garrigue