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| Date: | -- (:) |
| From: | Dario Teixeira <darioteixeira@y...> |
| Subject: | Unusual type declaration and Sexplib |
Hi,
I'm having some trouble serialising via Sexplib a data structure defined
recursively. Consider module M defined below; note how type foobar_t includes
a "with sexp" declaration, telling the Sexplib syntax extension to create
(de)serialisers automatically. However, type t cannot rely on that automatism,
because type declarations with the "as" operator are not fully supported.
Therefore, I need to create the (de)serialisers for this type manually.
module M:
sig
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list
] with sexp
type t = private [< 'a foobar_t ] as 'a
val foo: int -> t
val bar: t list -> t
end =
struct
type 'a foobar_t =
[ `Foo of int
| `Bar of 'a list
] with sexp
type t = 'a foobar_t as 'a
let foo x = `Foo x
let bar x = `Bar x
end
So basically the problem is creating the functions with the following signatures:
val sexp_of_t: t -> Sexplib.Sexp.t
val t_of_sexp: Sexplib.Sexp.t -> t
Using as base the automatically created functions whose signatures are as follows:
val sexp_of_foobar_t: ('a -> Sexplib.Sexp.t) -> 'a foobar_t -> Sexplib.Sexp.t
val foobar_t_of_sexp: (Sexplib.Sexp.t -> 'a) -> Sexplib.Sexp.t -> 'a foobar_t
But in practice, I'm having trouble seeing how these later functions can
be used. The problem lies in their recursive definition: how would I
break it? (And yes, I realise that the definition of type t is unusual,
but it's extremely convenient for avoiding a lot of explicit annotations
and coercions [1]).
Thanks for your help!
Best regards,
Dario Teixeira
[1] http://groups.google.com/group/fa.caml/browse_thread/thread/7552095ab859fb5f/9c4a6fd19812fbcc