Version française
Home     About     Download     Resources     Contact us    
Browse thread
Question about the -dlambda option of ocamlc/ocamlopt
[ Home ] [ Index: by date | by threads ]
[ Search: ]

[ Message by date: previous | next ] [ Message in thread: previous | next ] [ Thread: previous | next ]
Date: -- (:)
From: Romain Bardou <Romain.Bardou@l...>
Subject: Re: [Caml-list] Question about the -dlambda option of ocamlc/ocamlopt
Alp Mestan a écrit :
> Hi,
> 
> I'm currently studying the lambda code generation phase of the standard 
> OCaml compiler.
> 
> You can take a look at this for an example : 
> http://blog.mestan.fr/2009/03/22/ocaml-and-dlambda-1/
> 
> I'm wondering what is 'makeblock' for ?
> And why is there '/<a number>' after every variable/function name ? 
> Isn't the name sufficient for identifying variables ?
> 
> Thanks !

If I recall correctly, makeblock is for block allocation and is used to 
make empty blocks for everything that does not fit in just one integer.

The /<a number> is used to uniquely identify identifiers. In this example :

let x = 1 in let x = 2 in x

The /<a number> allows you to know which "let" variable is represented 
by the "x" at the end.

-- 
Romain Bardou