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Threads Scheduling
- Gregory Malecha
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Date: | 2010-04-13 (20:34) |
From: | Gregory Malecha <gmalecha@e...> |
Subject: | Threads Scheduling |
Hello, I'm trying to write a function (run_guarded) that takes another function (f), and runs it for some amount of time. If f terminates with value x, then the result of run_guarded should be Some x, otherwise it should be None. Here's my implementation using the Thread library: let run_guarded f x = let res = ref None in let m = Mutex.create () in let c = Condition.create () in let _ = Mutex.lock m in let tid1 = Thread.create (fun x -> let z = f x in let _ = res := Some z in let _ = Mutex.lock m in let _ = Mutex.unlock m in let _ = Condition.broadcast c in ()) x and tid2 = Thread.create (fun () -> let _ = Thread.delay 0.3 in let _ = Mutex.lock m in let _ = Mutex.unlock m in let _ = Condition.broadcast c in ()) () in let _ = Condition.wait c m in let _ = Mutex.unlock m in let _ = try Thread.kill tid2 with _ -> () in let _ = try Thread.kill tid1 with _ -> () in !res It seems like it should work, but it doesn't work if the function f doesn't terminate. It seems to be running everything serially. I know that threads aren't actually parallel, but I thought they were preemptive in which case it seems like this should work. Does anyone know what I did wrong here? Thank you very much. -- gregory malecha