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Re: [Caml-list] Code-execution (evaluation) time
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Date: -- (:)
From: mark@p...
Subject: Re: [Caml-list] Code-execution (evaluation) time
It's also worth noting a few other things about execution order:

1) function call arguments - All arguments in a function call are evaluated,
even if not needed (in right-to-left order - as David says - but don't rely
on this).

2) function bodies - These are executed when at least as many arguments are
supplied as are explicitly supplied in the definition of the function.  For

let f x = (print_string "X"; fun y -> (print_string "Y"; x + y));;
- this will not print anything as 'f' is defined

let g = f 5;;
- this will print "X" as 'g' is defined
- "Y" will be printed each time 'g' is called with an argument.

3) blank assignments - These are still fully evaluated, even though the
results are thrown away.  For example:

let _ = (print_string "X"; 5);;
- this will still print "X"

4) 'match' branch choice - The first matching branch (i.e. as it appears in
the file) is chosen (if the conditions overlap).

5) 'if' and 'match' unused branches - These (obviously) don't execute at
all.  So these do not behave like functions.

6) logical operator short circuits - '||' and '&&' short-circuit
left-to-right (i.e. don't evaluate the second argument if the first (i.e.
leftmost) argument is "true" (for '||') or "false (for '&&').  So these do
not behave like functions.  For example:

let foo x y = x && y;;

(print_string "X"; false) && (print_string "Y"; false);;
- this will print just "X"

foo (print_string "X"; false) (print_string "Y"; false);;
- this will print "YX", because it's a function call and not a logical


on 19/10/10 8:54 PM, David Allsopp <> wrote:

> Oliver Bandel wrote:
>> Hello,
>> I want to refresh my OCaml knowledge after I (again) paused for a while.
>> I want to know, when certain parts of the code are executed,
>> for example if I have more than one   let _ = ...
>> statement in my code (for example in different comp0ilaion units each one
>> of them).
> Expressions (as in, things listed in
> are evaluated in the
> order in which they appear in a source file. If you have two files
> which contain top-level statements, the order in which they execute
> will depend on the order in which you link the resulting .cmo or .cmx
> (which should be left-to-right as passed to ocamlc/ocamlopt - don't know
> where that's specified).
> As far as I can see, in pretty much all contexts within an expression
> order of evaluation could matter including, but probably not limited to:
> * Record initialisation (e.g. let i = ref 0 in {a = (incr i; !i); b =
> i; !i)})
> * Function application (similarly)
> * let foo = _ and bar = _ in _
> are intentionally left as unspecified (in practice, application and record
> initialisation are right-to-left and let x = _ and y = _ is left-to-right
> but the point is that you are never supposed to rely on that).
>> I also found an old code snippet with the following parts:
>> ==============================
>> let fnames = Sys.argv)
>> (* some more code *)
>> let _ =
>>    List.iter print_days_old fnames
>> ==============================
>> So, the value fnames contains the args from the command line and can be
>> used in the first statement of the code.
> [let fnames = ..] is a complete expression so it's evaluated before the
> _] further down.
> David