]> My CAML skills are poor, especially on bitwise operations, but here is how one does (or can do) unsigned in Java: public static boolean lessThan(int x, int y) { return ((x^y) >= 0) ? (x < y) : (y < x); }; That is, if the signs are the same, then signed and unsigned compares agree. Otherwise, the negative one is larger. Another way to phrase this might be (if you hate control flow): return ((x^y) >>> 31) ^ (x < y); The reasoning here is that if the signs agree, then 0 XOR any == any. Otherwise, if the signs disagree, then x and y are surely not equal, so (y<x) and (y<=x) serve equally well, but (y<=x) == !(x<y), which has a subexpression in common with the other case. Hope this helps. David ------------------- To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ Beginner's list: http://groups.yahoo.com/group/ocaml_beginners