]> Hi list, I have the following functor : module Make(A : sig type a val f : a -> int end) = struct type t = [ A.a | `B ] (* impossible : A.a is abstract and not a variant *) let foo = function | #A.a as a -> A.f a (* no assumption about the tags of A.a *) | `B -> 0 end I'd like to know if it is possible to describe A.a as a variant type without write its tags. Cheers, Julien Signoles. -- mailto : Julien.Signoles@lri.fr ; http : www.lri.fr/~signoles "In theory, practice and theory are the same, but in practice they are different" (Larry McVoy) ------------------- To unsubscribe, mail caml-list-request@inria.fr Archives: http://caml.inria.fr Bug reports: http://caml.inria.fr/bin/caml-bugs FAQ: http://caml.inria.fr/FAQ/ Beginner's list: http://groups.yahoo.com/group/ocaml_beginners