Damien Doligez wrote:
> 
> >From: Max Skaller <maxs@in.ot.com.au>
> >
> >Alternatively, you can just use
> >
> >       let rec x' () = ...
> >       and ...
> >       let x = x()
> >
> >in lieu of what you really wanted: (that is,
> >there is a workaround).
> 
> But that doesn't work for "let rec x = 1 :: x", which is the most
> interesting feature of O'Caml's recursive value definitions.
        It doesn't?
        let rec x'() = 1 :: x()'
        let x = x'()
Seems to work fine. Of course, this will loop forever in an eager
language: the result is an infinite list of 1s.
-- John (Max) Skaller at OTT [Open Telecommications Ltd] mailto:maxs@in.ot.com.au -- at work mailto:skaller@maxtal.com.au -- at home
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