Re: variables in 'let rec'

From: John Max Skaller (skaller@maxtal.com.au)
Date: Thu Mar 30 2000 - 11:19:16 MET DST

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Damien Doligez wrote:
>
> >From: Max Skaller <maxs@in.ot.com.au>
>
> > let rec x'() = 1 :: x()'
> > let x = x'()
> >
> >Seems to work fine. Of course, this will loop forever in an eager
> >language: the result is an infinite list of 1s.
>
> Looping forever is not quite the same as returning an infinite list
> of 1s, which is what the current implementation does for
> let rec x = 1::x

I don't understand: to construct an infinite list of 1's would seem to
me to take infinite time in an eager language. So it comes to the same
thing, doesn't it?

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